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Math · Integrated Math 1

Chapter 1: Expressions and Equations

Solving Linear Equations

Undo the operations, one at a time.

Lesson
1
Time
About 20 minutes
0 of 12 done
Part 1 of 7Let's Learn

Step 1: Let's Learn

Read it, or press Listen and follow the words.

Watch the idea first — 53 seconds. Then read on, and try it yourself in the next step.

Solve 3x + 5 = 20

  1. 13x + 5 = 20the equation as given
  2. 23x = 15− 5the 5 was added last, so it comes off first
  3. Answerx = 5÷ 3undo the multiplication
  4. 43(5) + 5 = 20check in the original

An equation is a balance: whatever you do to one side must be done to the other. To isolate x, undo the operations in the opposite order they were applied: addition and subtraction come off before multiplication and division. Then substitute the answer back.

Clear the brackets first

3(x + 2) = 15: distribute to 3x + 6 = 15, then 3x = 9, x = 3. Or divide both sides by 3 first: x + 2 = 5, x = 3. Both are valid; the second is shorter when the right side divides cleanly.

Variables on both sides

5x + 3 = 2x + 12: subtract 2x from both sides, 3x + 3 = 12, then 3x = 9, x = 3. Collect the variable terms on whichever side keeps the coefficient positive; it avoids a sign error later.

Fractions

x/4 + 3 = 7: subtract 3, x/4 = 4, multiply by 4, x = 16. Or clear the fraction first by multiplying everything by 4: x + 12 = 28. Either way, one operation at a time.

Two special outcomes

2(x + 3) = 2x + 6 becomes 6 = 6: true for every x, infinitely many solutions. 2(x + 3) = 2x + 1 becomes 6 = 1: false, no solution. When the variables vanish, the statement left behind decides.

Justify each step

Write the move beside each line: "subtract 5 from both sides", "divide both sides by 3". The justification is what makes the working a proof that x = 5, not just a guess that happens to work.

Always check

Substitute the answer into the original equation, not into a later line. 3(5) + 5 = 20 holds. It costs one line and catches nearly every arithmetic slip.

Step 2: Try It Yourself

Tap and try it out.

Press Next step. Brackets first, then gather the x terms, then the numbers.

Solve 4(x − 2) = 2x + 6

  1. 14x − 8 = 2x + 6distribute the 4
Step 0 of 4
x tiles and units on the left, units on the right. Take the same from both sides until the x tiles stand alone, then share.

3x + 5 = 20

3x + 5 balances 20. Take the same off both pans and they stay level, because the same was done to each side.

Step 3: In Real Life

A phone bill

A bill of 47 dollars on a plan of 20 plus 0.05 a text: 20 + 0.05t = 47. Undo the 20, then the 0.05: 540 texts. Every bill is an equation with one unknown.

Step 4: Watch an Example

One step at a time.

Watch Amara Solve 3x + 5 = 20

Amara needs the value of x.

  1. Step 1

    The 5 was added last, so it comes off first: subtract 5 from both sides, leaving 3x = 15.

Step 5: Your Turn

Practice makes it stick.

The Equation

Problem 1 of 2

2x + 7 = 19. What is x?

The Tickets

Problem 2 of 2

Tickets cost $8 each plus a $5 booking fee. A total of $53 buys how many tickets?

Isolate the Variable

1 of 8

x + 9 = 15. What is x?

2 of 8

4x = 28. What is x?

3 of 8

5x − 3 = 22. What is x?

4 of 8

3(x + 2) = 18. What is x?

5 of 8

7x = 4x + 12. What is x?

6 of 8

2x + 3 = 2x + 9. How many solutions?

7 of 8

Put the solving steps for 3x + 5 = 20 in order.

  1. 1Simplify to 3x = 15.
  2. 2Divide both sides by 3.
  3. 3Check by substituting back.
  4. 4Subtract 5 from both sides.

8 of 8

6x − 4 = 2x + 12. What is x?

Step 6: Quick Check

Show what you know.

Question 1 of 2

4x + 6 = 26. What is x?

Question 2 of 2

The variables cancel and leave 7 = 7. How many solutions?

What You Learned

  • An equation is a balance; do the same to both sides, and write the move beside each line.
  • Undo operations in the reverse of the order they were applied; clear brackets first.
  • Vanishing variables leave either every solution or none.
  • Substitute your answer into the original equation every time.